To find the total, number of ways in which either of the two jobs can be performed when both the jobs are mutually exclusive jobs the fundamental principle is followed. If the two jobs can be performed independently in m and n ways respectively, then either of the two jobs can be performed in ( m+ n) ways.
In case of two events X and Y. n(X) denotes the possible ways in which the event X can occurs n(Y) denotes the possible ways in which the event Y can occurs
Let Z be an event describing the situation in which either event X occurs, OR event Y occurs. Then, if n(Z) denotes the number of ways in which the event Z can occur or the number of possible outcomes of the event Z . It can be calculated using the Fundamental Principle of Addition and is given by:
n(Z) = n(X) + n(Y)
For example: To calculate the total number of possible outcomes when either a coin is tossed or a dice is thrown the Fundamental Principle of Addition can be used as follows
Job 1: When a dice is thrown the possible outcomes are n(dice)= 6
Job 2: When a coin is tossed the possible outcomes are n(coin)= 2
The total number of possible outcomes when either a coin is tossed or a dice is thrown can be calculated as
n(dice or coin) = n(dice) + n(coin) =6 + 2= 8
In a box there are 10 red balls and 5 white balls. The shopkeeper wants to withdraw either a red ball or a white ball to display in showcase. In how many ways the shopkeeper can make this selection ? | |||
Right Option : A | |||
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In a school there are 15 candidates for Science scholarship and 20 candidates for English scholarship. In how many ways either of these scholarships will be awarded? | |||
Right Option : A | |||
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Which of the following statement is/are correct? (a) In a class there are 4 boys and 3 girls. Teacher wants to select a boy or a girl . Teacher can make selection in 12 ways. (b) In a shop there are 5 candies and 5 chocolates. A child wants to have a candy or a chocolate. A child can have a candy or a chocolate in 25 ways. | |||
Right Option : D | |||
View Explanation |
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